Your head of powertrain has found a battery cell with excellent specifications and yet cheap. He decides upon a 142s2p accumulator configuration using the cells with a capacity of 5.8 Ah. The manufacturer specifies an internal impedance of 1.5 mOhm. However, after a while you notice the cells are horrible quality and their real capacity caries significantly leading to an unbalanced accumulator. He performed experiments to find an approximation of the cells SoC relation to their open-circuit volage (EMF) as shown in the following figure: Assume due to imbalance, exactly half of the accumulators cells are at 40% SoC and half at 80% SoC. What current will be drawn at the maximum allowed power usage? (answer in A) Round the voltage in the figure and the answer to the nearest decimal (e.g. 3.15V becomes 3.2V and 1.15 A becomes 1.2 A) Please use the following format: 12.3 or 1.23 (no ',' comma, no latters), round to 3 significant digits.
AI image description
Two side-by-side graphs. Left, "State of Charge vs. Cell voltage": x-axis State of Charge [-], 0–100; y-axis Voltage [V], approximately 3.0–4.2. Orange open-circle measurement points scatter around a blue approximation curve, which rises steeply near 0% and 100% SOC and gradually through the middle; thin reference lines appear near 40% and 80% SOC and around 3.7 and 3.8 V. Right, "State of Charge vs. Cell impedance": x-axis State of Charge [-] from 0 to 100; y-axis Internal impedance [mΩ] from 1 to 2. A descending straight blue line joins approximately (0, 2.0 mΩ) and (100, 1.0 mΩ).
- 153-156Correct
Official answer
153-156

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- FSCH 2021 · ev · quiz 18